Surveying — Quiz 4
Questions in this quiz (10)
For a horizontal curve with a radius of $$1100\ \mathrm{ft}$$, determine the tangent offset at a point $$180\ \mathrm{ft}$$ along the tangent from the PC. Use the approximate formula $$Y=\frac{X^2}{2R}$$.
- $$14.73\ \mathrm{ft}$$
- $$12.50\ \mathrm{ft}$$
- $$10.64\ \mathrm{ft}$$
- $$18.20\ \mathrm{ft}$$
A sag vertical curve must provide adequate headlight sight distance of $$350\ \mathrm{ft}$$. If the algebraic difference between the grades is $$5.2\%$$, determine the minimum curve length required. Use the formula $$L=\frac{AS^2}{400+3.5S}$$.
- $$460.6\ \mathrm{ft}$$
- $$530.2\ \mathrm{ft}$$
- $$392.0\ \mathrm{ft}$$
- $$612.3\ \mathrm{ft}$$
A three-level roadway cross-section has a $$28$$-ft wide roadbed ($$14\ \mathrm{ft}$$ each side of centerline). At a particular station, the centerline cut depth is $$5.2\ \mathrm{ft}$$. The left slope stake is $$16\ \mathrm{ft}$$ from centerline and the right slope stake is $$22\ \mathrm{ft}$$ from centerline, both at ground level. Determine the cross-sectional area.
- $$201.4\ \mathrm{sq\ ft}$$
- $$171.6\ \mathrm{sq\ ft}$$
- $$158.6\ \mathrm{sq\ ft}$$
- $$189.2\ \mathrm{sq\ ft}$$
A horizontal curve with a radius of $$1200\ \mathrm{ft}$$ is designed for a speed of $$55\ \mathrm{mph}$$. Using the formula $$e+f=\frac{V^2}{15R}$$, where the side friction factor is $$f=0.13$$, determine the required superelevation rate.
- $$0.015\ \mathrm{ft/ft}$$
- $$0.028\ \mathrm{ft/ft}$$
- $$0.0381\ \mathrm{ft/ft}$$
- $$0.033\ \mathrm{ft/ft}$$
At a survey station, three angles are measured to close the horizon: $$92^\circ15^\prime20^{\prime\prime}$$, $$118^\circ42^\prime15^{\prime\prime}$$, and $$148^\circ02^\prime30^{\prime\prime}$$. Determine the angular closure error.
- $$+5^{\prime\prime}$$
- $$-5^{\prime\prime}$$
- $$+10^{\prime\prime}$$
- $$-10^{\prime\prime}$$
Three independent level runs are made to establish the elevation of a benchmark. The results are: Run 1 ($$3\ \mathrm{km}$$): $$512.438\ \mathrm{m}$$, Run 2 ($$5\ \mathrm{km}$$): $$512.421\ \mathrm{m}$$, Run 3 ($$2\ \mathrm{km}$$): $$512.445\ \mathrm{m}$$. Using weights inversely proportional to distance, determine the most probable elevation.
- $$512.436\ \mathrm{m}$$
- $$512.439\ \mathrm{m}$$
- $$512.438\ \mathrm{m}$$
- $$512.441\ \mathrm{m}$$
A stadia reading is taken with a vertical angle of $$+10^\circ15^\prime$$. The stadia interval is $$1.65\ \mathrm{ft}$$ and the stadia interval factor $$K$$ is $$100$$. Determine the horizontal distance.
- $$160.25\ \mathrm{ft}$$
- $$159.78\ \mathrm{ft}$$
- $$162.40\ \mathrm{ft}$$
- $$155.10\ \mathrm{ft}$$
An excavation yields $$6200$$ cubic yards of material measured in its natural (bank) state. If the material has a shrinkage factor of $$12\%$$ when compacted, determine the volume of compacted fill.
- $$5456\ \mathrm{cu\ yd}$$
- $$5300\ \mathrm{cu\ yd}$$
- $$5510\ \mathrm{cu\ yd}$$
- $$5620\ \mathrm{cu\ yd}$$
Two sides of a triangle are $$70\ \mathrm{ft}$$ and $$110\ \mathrm{ft}$$ with a $$55^\circ$$ angle between them. The length of the third side and remaining two angles are most nearly:
- $$92\ \mathrm{ft},\ 65^\circ,\ 60^\circ$$
- $$90.37\ \mathrm{ft},\ 39.38^\circ,\ 85.62^\circ$$
- $$85\ \mathrm{ft},\ 70^\circ,\ 55^\circ$$
- $$95\ \mathrm{ft},\ 60^\circ,\ 65^\circ$$
In an equilateral triangle, the height (altitude) is $$4\ \mathrm{ft}$$ less than its side. The sides of the triangle most nearly equal:
- $$12\ \mathrm{ft}$$
- $$18\ \mathrm{ft}$$
- $$24\ \mathrm{ft}$$
- $$30\ \mathrm{ft}$$
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