Transportation Engineering — Quiz 2
Questions in this quiz (10)
Given a parabolic vertical curve with VPC station $$14+44$$ at elevation $$792$$ $$ft$$, an entry grade of $$+2\%$$, an exit grade of $$-3\%$$, and length of $$600$$ $$ft$$, the elevation of the point of vertical tangency is most nearly:
- $$567\ \mathrm{ft}$$
- $$789\ \mathrm{ft}$$
- $$889\ \mathrm{ft}$$
- $$897\ \mathrm{ft}$$
A $$600\ \mathrm{ft}$$ long equal-tangent crest vertical curve connects grades of $$+4.0\%$$ and $$-2.5\%$$. The point of vertical intersection (PVI) is located at station $$123+00$$ with an elevation of $$62.80\ \mathrm{ft}$$. What is the elevation of the PVT?
- $$45.70\ \mathrm{ft}$$
- $$47.60\ \mathrm{ft}$$
- $$52.65\ \mathrm{ft}$$
- $$55.30\ \mathrm{ft}$$
A horizontal circular curve has an intersection angle of $$16^\circ$$. The length of middle ordinate $$M$$ is $$8.00\ \mathrm{ft}$$. The radius of the curve is most nearly:
- $$625.8\ \mathrm{ft}$$
- $$752.6\ \mathrm{ft}$$
- $$824.7\ \mathrm{ft}$$
- $$889.7\ \mathrm{ft}$$
A $$800\ \mathrm{ft}$$ symmetric vertical curve is provided for a highway crest vertical curve. The grade of the back tangent is $$+2\%$$ and the grade of the forward tangent is $$-2\%$$. The elevation of the point of vertical intersection (PVI) is $$1200.00\ \mathrm{ft}$$. What is the elevation of the point of vertical curve (PVC)?
- $$1192\ \mathrm{ft}$$
- $$1208\ \mathrm{ft}$$
- $$1184\ \mathrm{ft}$$
- $$1216\ \mathrm{ft}$$
A $$6^\circ$$ curve has forward and back tangents intersecting at station $$14+87.33$$. The intersection angle is $$11^\circ21'35''$$. The station of BC is most nearly:
- sta $$5+32.4$$
- sta $$9+92.6$$
- sta $$11+27.9$$
- sta $$13+92.4$$
A vertical curve has $$L=8$$ stations and PVI at $$87+00$$. Grades are $$-2.0\%$$ to $$+1.6\%$$. The low point station is:
- sta $$78+55$$
- sta $$87+00$$
- sta $$87+44$$
- sta $$91+00$$
Using Greenshields model, if jam density is $$150\ veh/mi$$, density at capacity is:
- $$15 veh/mi$$
- $$45 veh/mi$$
- $$75 veh/mi$$
- $$230 veh/mi$$
A curve has $$R=600\ ft$$ and $$I=18^\circ$$. External distance $$E$$ is:
- $$7.48$$
- $$8.47$$
- $$4.78$$
- $$7.84$$
A four-phase signal has startup lost time $$2s$$, yellow $$4s$$, all-red $$1.5s$$, extension $$2s$$. Total lost time:
- $$8 s$$
- $$16 s$$
- $$22 s$$
- $$20 s$$
A horizontal curve has its PC at station $$32+50.00$$ and a curve length of $$425\ \mathrm{ft}$$. What is the station of the PT?
- $$28+25.00$$
- $$36+75.00$$
- $$41+00.00$$
- $$32+50.00$$
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